1.2 KiB
1.2 KiB
layout, title, last_solved, category, leetcode_url, status
| layout | title | last_solved | category | leetcode_url | status |
|---|---|---|---|---|---|
| page | Binary Tree Zig Zag (DFS) | 2020-07-22 | bfs | https://leetcode.com/problems/binary-tree-zigzag-level-order-traversal | Attempted |
Problem
Given a binary tree, return the zigzag level order traversal of its nodes' values. (ie, from left to right, then right to left for the next level and alternate between).
For example:
Given binary tree [3,9,20,null,null,15,7],
3
/ \
9 20
/ \
15 7
return its zigzag level order traversal as:
[
[3],
[20,9],
[15,7]
]
Solution
{% highlight python %}
def zigzagLevelOrder(self, root: TreeNode) -> List[List[int]]:
output = []
def dfs(node, level, output):
if not node:
return
if len(output) <= level:
output += [[]]
dfs(node.left, level+1, output)
dfs(node.right, level+1, output)
if level%2==0:
output[level].append(node.val)
else:
output[level].insert(0, node.val)
dfs(root, 0, output)
return output
{% endhighlight %}