1.2 KiB
1.2 KiB
layout, title, last_solved, category, leetcode_url, status
| layout | title | last_solved | category | leetcode_url | status |
|---|---|---|---|---|---|
| page | Convert Sorted Array to Binary Search Tree | https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/ | Attempted |
Problem
Given an array where elements are sorted in ascending order, convert it to a height balanced BST.
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
Example:
Given the sorted array: [-10,-3,0,5,9],
One possible answer is: [0,-3,9,-10,null,5], which represents the following height balanced BST:
0
/ \
-3 9
/ /
-10 5
Solution
{% highlight python %}
def sortedArrayToBST(self, nums: List[int]) -> TreeNode:
def buildTree(nums, left, right):
if left>right: return
mid = (left+right) // 2
node = TreeNode(nums[mid])
node.left = buildTree(nums, left, mid-1)
node.right = buildTree(nums, mid+1, right)
return node
if not nums: return None
return buildTree(nums, 0, len(nums)-1)
{% endhighlight %}