leetcode_gym/_problems/groupIsomorphicStrings.md
2026-08-25 19:14:07 -06:00

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layout, title, last_solved, category, leetcode_url, status
layout title last_solved category leetcode_url status
page Group Isometric Strings 2020-06-11 hashmap https://leetcode.com/discuss/interview-question/368038/Amazon-or-Onsite-or-Group-Isomorphic-Strings Solved

Problem

Two strings are isomorphic if each character of their strings can be mapped to another character and retain the same "structure".

egg and add are isomorphic e->a, g->d

Given: [“foo”, “bar”, “paper”, “title”, “egg”, “add”]
Expected: [[“bar”],[“paper” “title”], [“egg”, “add”, "foo”]]

Solution

{% highlight python %}

def normalize(word):

res = ""
count = 0

map = {}
for c in word:
    if c not in map:
        map[c] = count
        count+=1
        res += str(map[c])
    else:
        res += str(map[c])

return res

def findIso(arr):

map = {}

# first pass to build map
for word in arr:
    if normalize(word) not in map:
        map[ normalize(word) ] = [word]
    else:
        # existingList = map[ normalize(word) ]
        # existingList.append(word)
        # map[ normalize(word) ] = existingList
        map[ normalize(word) ].append(word)

# second pass to extract grouped words in the map

result = []

for groupedWords in map.values():

result.append( groupedWords )

return result

return list( map.values() )

input1 = ["foo", "bar", "paper", "title", "egg", "add"] res = findIso(input1) print(res)

{% endhighlight %}

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