1.6 KiB
1.6 KiB
layout, title, last_solved, category, leetcode_url, status
| layout | title | last_solved | category | leetcode_url | status |
|---|---|---|---|---|---|
| page | Isomorphic Strings | 2020-08-04 | hashmap | https://leetcode.com/problems/isomorphic-strings | Solved |
Problem
Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
Example 1:
Input: s = "egg", t = "add"
Output: true
Example 2:
Input: s = "foo", t = "bar"
Output: false
Example 3:
Input: s = "paper", t = "title"
Output: true
Solution
{% highlight python %}
def isIsomorphic(self, s: str, t: str) -> bool:
"""
egg -> 011
add -> 011
"""
def isohash(word):
mapping = defaultdict(int) # key=character, value=seqNum
res = ""
seqNum = 0 # seqNum is number that was assigned to char, for "egg": e is assigned '1', g is assigned '2'
"""
mapping[e]=1
mapping[g]=2
"""
for c in word:
if c not in mapping:
mapping[c] = seqNum # assign a number to char (keep track of it in hashmap)
seqNum+=1 # increment seqNum by 1 for the next character
res += str(mapping[c]) # add seqNum to res
else:
res += str(mapping[c]) # if already assigned, just add to res
return res
return isohash(s)==isohash(t)
{% endhighlight %}