1.8 KiB
1.8 KiB
layout, title
| layout | title |
|---|---|
| page | Longest Common Subsequence |
Input: text1 = "abcde", text2 = "ace"
Output: 3
Explanation: The longest common subsequence is "ace" and its length is
Gotchas
- look out for the dimension with which you build the grid (ie: m<->i, n<->j)
- table=[[0]*(n+1) for x in range(m+1)]
- otherwise you could run into a array out of bounds error
{% highlight python %}
str1 = "AAB" str2 = "AZB"
def lcs(text1, text2):
n= len(text1)
m= len(text2)
# creates an [m+1][n+1] matrix, filled with zeros
table=[[0]*(n+1) for x in range(m+1)]
for i in range(1, m+1):
for j in range (1, n+1):
# first char is the same, so add 1 to count
if text2[i-1]==text1[j-1]:
table[i][j]= 1+table[i-1][j-1]
# first char is different, so break into subproblems and take the max
else:
table[i][j]=max(table[i-1][j],table[i][j-1])
print [0]*(n+1)
print range(m+1)
print table
print max(table) # this get the last element at the end of the list
return max(max(table)) # this gets the last element at the bottom right corner (last element of both lists)
print lcs(str1, str2)
{% endhighlight %}