1.4 KiB
1.4 KiB
layout, title, last_solved, category, leetcode_url, status
| layout | title | last_solved | category | leetcode_url | status |
|---|---|---|---|---|---|
| page | nth digit | math | https://leetcode.com/problems/nth-digit/ | Attempted |
Problem
Find the nth digit of the infinite integer sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ...
Note:
n is positive and will fit within the range of a 32-bit signed integer (n < 231).
Example 1:
Input:
3
Output:
3
Example 2:
Input:
11
Output:
0
Explanation:
The 11th digit of the sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ... is a 0, which is part of the number 10.
Solution
Do not understand logic yet. Learn from this discussion
{% highlight python %}
def findNthDigit(self, n: int) -> int:
# https://leetcode.com/problems/nth-digit/discuss/88369/0ms-C%2B%2B-Solution-with-Detail-Explanation
# 1) find out how many digits the number has (n=250, digits=3)
base=9
digits=1
while n-base*digits > 0:
n-=base*digits
base*=10
digits+=1
print(n, base, digits)
# 2) calc what the number is
index = (n-1) % digits
offset = (n-1) / digits
start = pow(10, digits-1)
print(index, offset, start)
return str(int(start+offset))[index]
{% endhighlight %}