1.6 KiB
1.6 KiB
layout, title, last_solved, category, leetcode_url, status
| layout | title | last_solved | category | leetcode_url | status |
|---|---|---|---|---|---|
| page | Path Sum 3 | tree | https://leetcode.com/problems/path-sum-iii/ | Attempted |
Problem
You are given a binary tree in which each node contains an integer value.
Find the number of paths that sum to a given value.
The path does not need to start or end at the root or a leaf, but it must go downwards (traveling only from parent nodes to child nodes).
The tree has no more than 1,000 nodes and the values are in the range -1,000,000 to 1,000,000.
Example:
root = [10,5,-3,3,2,null,11,3,-2,null,1], sum = 8
10
/ \
5 -3
/ \ \
3 2 11
/ \ \
3 -2 1
Return 3. The paths that sum to 8 are:
1. 5 -> 3
2. 5 -> 2 -> 1
3. -3 -> 11
Solution
This is a double nested dfs solution so runtime is horrible but it still works.
{% highlight python %}
def pathSum(self, root: TreeNode, sum: int) -> int:
self.total = 0
def helper(node, currSum):
if not node:
return
helper(node.left, currSum+node.val)
helper(node.right, currSum+node.val)
if node.val + currSum == sum:
self.total+=1
def dfs(node):
if not node: return
helper(node, 0)
dfs(node.left)
dfs(node.right)
dfs(root)
return self.total
{% endhighlight %}
{% highlight python %}
{% endhighlight %}