71 lines
1.8 KiB
Markdown
71 lines
1.8 KiB
Markdown
---
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layout: page
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title: The PADS
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last_solved:
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category: sql
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leetcode_url: https://www.hackerrank.com/challenges/the-pads/problem
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status: Attempted
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---
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Problem
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-------
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```
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Generate the following two result sets:
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Query an alphabetically ordered list of all names in OCCUPATIONS, immediately followed by the first letter of each profession as a parenthetical (i.e.: enclosed in parentheses). For example: AnActorName(A), ADoctorName(D), AProfessorName(P), and ASingerName(S).
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Query the number of ocurrences of each occupation in OCCUPATIONS. Sort the occurrences in ascending order, and output them in the following format:
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There are a total of [occupation_count] [occupation]s.
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where [occupation_count] is the number of occurrences of an occupation in OCCUPATIONS and [occupation] is the lowercase occupation name. If more than one Occupation has the same [occupation_count], they should be ordered alphabetically.
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Note: There will be at least two entries in the table for each type of occupation.
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Input Format
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The OCCUPATIONS table is described as follows: Occupation will only contain one of the following values: Doctor, Professor, Singer or Actor.
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Sample Input
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An OCCUPATIONS table that contains the following records:
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Sample Output
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Ashely(P)
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Christeen(P)
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Jane(A)
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Jenny(D)
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Julia(A)
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Ketty(P)
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Maria(A)
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Meera(S)
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Priya(S)
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Samantha(D)
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There are a total of 2 doctors.
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There are a total of 2 singers.
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There are a total of 3 actors.
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There are a total of 3 professors.
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```
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Solution
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----------
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{% highlight sql %}
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select concat(name, "(", substring(occupation, 1,1), ")")
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from occupations
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order by name;
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select concat("There are a total of ", count(*), " ", lower(occupation), "s.")
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from occupations
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group by occupation
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order by count(*), occupation;
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{% endhighlight %}
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![image1]() |